Roberto Ierusalimschy f9d857a81b Stack reallocation done in two phases ...

$he stack reallocation is done in two steps (allocation + free) because
the correction of the pointers pointing into the stack must be done
while both addresses (the old stack and the new one) are valid.  In ISO
C, any pointer use after the pointer has been deallocated is undefined
behavior. The compiler option '-fsanitize=pointer-subtract' (plus what
it needs to work) complained about the old implementation.

2021-02-27 12:56:09 -03:00

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